C语言计算斐波那契数列
打印 N 的斐波那契数列,代码如下:
How many Fibonacci numbers do you want to compute? 9
I Fibonacci(I)
=====================
1 1
2 1
3 2
4 3
5 5
6 8
7 13
8 21
9 34
#include <stdio.h> int main(void) { int n; // 输入一个数字 N int i; // 第 i 个将要输出的斐波那契数 int current; // 第 i 个斐波那契数的值 int next; // 下一个(i+1)斐波那契数的值 int twoaway; // 下下个(i+2)斐波那契数的值 printf("How many Fibonacci numbers do you want to compute? "); scanf("%d", &n); if (n<=0) printf("The number should be positive.\n"); else { printf("\n\n\tI \t Fibonacci(I) \n\t=====================\n"); next = current = 1; for (i=1; i<=n; i++) { printf("\t%d \t %d\n", i, current); twoaway = current+next; current = next; next = twoaway; } } }可能的输出结果:
How many Fibonacci numbers do you want to compute? 9
I Fibonacci(I)
=====================
1 1
2 1
3 2
4 3
5 5
6 8
7 13
8 21
9 34