C语言读入一个数组并检索某个值是否在数组中

下面的程序，会读入一个整数数组，并对数组中的元素进行搜索，判断给定的值是否在数组中。

#include <stdio.h>

#define NMAX 10

int getIntArray(int a[], int nmax, int sentinel);
void printIntArray(int a[], int n);
int linear(int a[], int n, int who);

int main(void) {
    int x[NMAX];
    int hmny;
    int who;
    int where;

    hmny = getIntArray(x, NMAX, 0);
    printf("The array was: \n");
    printIntArray(x,hmny);
    printf("Now we do linear searches on this data\n");
    do{
        printf("Enter integer to search for [0 to terminate] : ");
        scanf("%d", &who);
        if(who==0) break;
        where = linear(x,hmny,who);
        if (where<0){
            printf("Sorry, %d is not in the array\n",who);
        }else{
            printf("%d is at position %d\n",who,where);
        }
    }while(1);
}

// n 为数组 a 中元素的个数；数组中的值被输出，5 个每行
void printIntArray(int a[], int n)
{
    int i;

    for (i=0; i<n; ){
        printf("\t%d ", a[i++]);
        if (i%5==0)
            printf("\n");
    }
    printf("\n");
}

// 最多读取 n 个整数并存储在数组 a 中
int getIntArray(int a[], int nmax, int sentinel)
{
    int n = 0;
    int temp;

    printf("Enter integer [%d to terminate] : ", sentinel);

    do {
        scanf("%d", &temp);
        if (temp==sentinel) break;
        if (n==nmax)
            printf("array is full! Enter integer [%d to terminate] : ", sentinel);
        else
            a[n++] = temp;
    }while (1);
    return n;
}

// 对数组 a 中的元素进行搜索；如果找到返回该元素的位置，否则返回 -1
int linear(int a[], int n, int who)
{
    int lcv;
    for (lcv=0;lcv<n;lcv++)
        if(who == a[lcv])return lcv;
    return (-1);
}

可能的输出结果：
Enter integer [0 to terminate] : 12 34 56 78 90 34464 2312 464 0
The array was:
    12            34          56        78    90
    34464     2312     464
Now we do linear searches on this data
Enter integer to search for [0 to terminate] : 12
12 is at position 0
Enter integer to search for [0 to terminate] : 56
56 is at position 2
Enter integer to search for [0 to terminate] : 34232
Sorry, 34232 is not in the array
Enter integer to search for [0 to terminate] : 0
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