Number of 1 Bits

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer 11 has binary representation 00000000000000000000000000001011, so the function should return 3.

题目翻译: 给出一个整数,求它包含二进制1的位数。例如,32位整数11的二进制表达形式是00000000000000000000000000001011,那么函数应该返回3。

题目分析: 设输入的数为n,把n与1做二进制的与(AND)运算,即可判断它的最低位是否为1。如果是的话,把计数变量加一。然后把n向右移动一位,重复上述操作。当n变为0时,终止算法,输出结果。

时间复杂度:O(n) 空间复杂度:O(1)

代码如下:

class Solution {
public:
    int hammingWeight(uint32_t n) {
        int count = 0;
        while (n > 0) {
            count += n & 1;
            n >>= 1;
        }
        return count;
    }
};